Min Max Algorithm using Divide and Conquer

Algorithm MaxMin(i,j,max,min)

{

if (i = j) then max:=min:=a[i]; elseif (i = j-1) then

{

if (a[i]<a[j])then

{

max :=a[j];min :=a[i];

}

else

{

max:=a[i];min:=a[j];

}

}

else

{

mid:=[(i+j)/2]; MaxMin(i,mid,max,min); MaxMin(mid+l,j,maxl,minl); if (max<maxl) then max:=maxl; if (min >mini)then min:=min1;

}

}


Source Code:

def MaxMin(i, j, max, min, a): if i == j:

max = min = a[i] elif i == j - 1:

if a[i] < a[j]: max = a[j] min = a[i]

else:

max = a[i] min = a[j]

else:

mid = (i+j) // 2

maxl, minl = MaxMin(i, mid, max, min,a) maxr, minr=MaxMin(mid+1,j,max,min,a) 

if max < maxr:

    max = maxr 

if min > minr: 

    min = minr

if max<maxl:

max=max1

if min >minl: 

min =minl

return max,min

a = [3, 1, 4, 2, 9, 8, 5, 6, 7, 3]

max_val, min_val = MaxMin(0, len(a)-1, a[0], a[0], a) print("Input array:", a)

print("Max value:", max_val) print("Min value:", min_val)


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